SOLUTION: factoring z^2+18z+45

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: factoring z^2+18z+45      Log On


   



Question 119700: factoring z^2+18z+45
Found 2 solutions by scott8148, jim_thompson5910:
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
the b coefficient is a combination of factors of the c term __ (z+15)(z+3)

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

Looking at z%5E2%2B18z%2B45 we can see that the first term is z%5E2 and the last term is 45 where the coefficients are 1 and 45 respectively.

Now multiply the first coefficient 1 and the last coefficient 45 to get 45. Now what two numbers multiply to 45 and add to the middle coefficient 18? Let's list all of the factors of 45:



Factors of 45:
1,3,5,9,15,45

-1,-3,-5,-9,-15,-45 ...List the negative factors as well. This will allow us to find all possible combinations

These factors pair up and multiply to 45
1*45
3*15
5*9
(-1)*(-45)
(-3)*(-15)
(-5)*(-9)

note: remember two negative numbers multiplied together make a positive number


Now which of these pairs add to 18? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 18

First NumberSecond NumberSum
1451+45=46
3153+15=18
595+9=14
-1-45-1+(-45)=-46
-3-15-3+(-15)=-18
-5-9-5+(-9)=-14



From this list we can see that 3 and 15 add up to 18 and multiply to 45


Now looking at the expression z%5E2%2B18z%2B45, replace 18z with 3z%2B15z (notice 3z%2B15z adds up to 18z. So it is equivalent to 18z)

z%5E2%2Bhighlight%283z%2B15z%29%2B45


Now let's factor z%5E2%2B3z%2B15z%2B45 by grouping:


%28z%5E2%2B3z%29%2B%2815z%2B45%29 Group like terms


z%28z%2B3%29%2B15%28z%2B3%29 Factor out the GCF of z out of the first group. Factor out the GCF of 15 out of the second group


%28z%2B15%29%28z%2B3%29 Since we have a common term of z%2B3, we can combine like terms

So z%5E2%2B3z%2B15z%2B45 factors to %28z%2B15%29%28z%2B3%29


So this also means that z%5E2%2B18z%2B45 factors to %28z%2B15%29%28z%2B3%29 (since z%5E2%2B18z%2B45 is equivalent to z%5E2%2B3z%2B15z%2B45)



------------------------------------------------------------



Answer:
So z%5E2%2B18z%2B45 factors to %28z%2B15%29%28z%2B3%29