Question 1196909: In the game of roulette, a wheel consists of 38 slots numbered 0, 00, 1, 2, ..., 36. The odd-numbered slots are red and the even-numbered slots are black. The slots with 0 and 00 are green. To play the game, a metal ball is spun around the wheel and is allowed to fall into one of the numbered slots.
1. The probability that the metal ball lands on green or red is .
2. The probability that the metal ball does not land on green is
Answer by math_helper(2461)   (Show Source):
You can put this solution on YOUR website!
To find the probability of x, P(x), count or compute the number of favorable outcomes and divide it by the total number of possible outcomes.
1. P(green or red) = (2+18)/38 = 20/38 = 10/19 or about 0.5263
2. P(not green) = (18+18)/38 = 36/38 = 18/19 or about 0.9474
P(not green) can also be found from 1 - P(green): 1 - (2/38) = 38/38 - 2/38 = 36/38, as above.
In a similar way, P(green or red) = 1 - P(black). You can check it for yourself.
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