SOLUTION: DATA CHART https://imagizer.imageshack.com/img922/1214/IzuZwz.png
a) Find the conditional probability of survival for each type of ticket.
​P(Survived | ​First-class)
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a) Find the conditional probability of survival for each type of ticket.
​P(Survived | ​First-class)
 â€
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Question 1196670: DATA CHART https://imagizer.imageshack.com/img922/1214/IzuZwz.png
a) Find the conditional probability of survival for each type of ticket.
​P(Survived | ​First-class)
  
enter your response here
​P(Survived | ​Second-class)
  
enter your response here
​P(Survived | ​Third-class)
  
enter your response here
​P(Survived | ​Crew)
  
enter your response here
​(Round to three decimal places as​ needed.)
Given that a passenger ​, what is the probability they had a ​-class ​ticket?
   Found 2 solutions by ikleyn, math_tutor2020:Answer by ikleyn(52794) (Show Source):
For each category, the same formula works
P = .
For example, in the first class
P(conditional probability to survive in first class) = = = 0.6414 (rounded). ANSWER
Do the same as instructed for each other category.
So asking something like P(survived | first class) means we know the person is in first class.
Since we can rewrite it as P(Survived given they are in first class)
There are 220+123 = 343 such people in first class.
Of this group of 343 people, 220 survived.
Therefore, 220/343 = 0.641 approximately is the probability of a survivor given they are in first class.
We do the same thing for parts 2 through 4.
I'll do the second part and leave parts 3 and 4 for you to do on your own.
P(survived given second-class) = (number of second-class survivors)/(number of people in second-class)
P(survived given second-class) = (114)/(114+171)
P(survived given second-class) = 114/285
P(survived given second-class) = 0.4 exactly
The last part of your question is garbled and missing important info.
You wrote "given that a passenger ____, what is the probability they had a ____ class ticket" but forgot to fill in those blanks
I'll go over an example
Question: given that a passenger survived , what is the probability they had a first class ticket?
Solution:
There are 713 total survivors, which is the total of everything along row one (ignore the 713 in that row since it's the result of adding everything else)
220+114+174+205 = 713
There are 220 survivors from first class (upper left corner)
The probability we get is therefore 220/713 = 0.309 approximately
If we know for certain the person is a survivor, then there's a 30.9% chance they are from first class.
Once again, this answer applies to a hypothetical example since I don't know what the full original question was. But you'll use this example template to answer your specific question.
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