.
Solve for all values of x in the interval [0, 2𝜋] that satisfy the equation.
4 sin(2x) = 4 cos(x)
~~~~~~~~~~~~~~~~
4 sin(2x) = 4 cos(x) implies, by canceling common factor "4" in both sides
sin(2x) = cos(x),
2sin(x)*cos(x) = cos(x)
2sin(x)*cos(x) - cos(x) = 0
cos(x)*(2sin(x) - 1) = 0
So, EITHER cos(x) = 0, OR sin(x) = 1/2.
If cos(x) = 0, then x=
or x=
.
If sin(x) = 1/2, then x=
or x=
-
=
.
So, the solution to the given equation are
,
,
,
. ANSWER
Solved.