SOLUTION: I don't really understand how to do this problem and would appreciate to know the steps. "In the previous baseball season, team A won the most games of any major league team. Team

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Question 1196620: I don't really understand how to do this problem and would appreciate to know the steps. "In the previous baseball season, team A won the most games of any major league team. Team A won 36 less than twice as many games as they lost. They played 162
regular-season games. How many wins and losses did team A have?" <--- word problem
-Ariel
Found 2 solutions by MathLover1, MathTherapy:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

.
let games as they won be x
and games as they lost be y
total games played 162+
x%2By=162.........eq.1
if team A won 36 less than twice as many games as they+lost, we have
x=2y-36............eq.2, substitute in eq.1
2y-36%2By=162........solve for y
3y=162%2B36
3y=198
y=66
go to
x=2y-36............eq.2, substitute y
x=2%2A66-36
x=132-36
x=96
team A did have 96 wins and 66 losses

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

I don't really understand how to do this problem and would appreciate to know the steps. "In the previous baseball season, team A won the most games of any major league team. Team A won 36 less than twice as many games as they lost. They played 162
regular-season games. How many wins and losses did team A have?" <--- word problem
-Ariel
Just ONE (1) variable is needed to solve this!

Let number of losses be L
Then number of wins = 2L - 36
With number of games played being 162, we get: L + 2L - 36 = 162
                                                        3L = 162 + 36
                                                        3L = 198
                               Number of losses, or 

                               Number of wins: 

                               It's as SIMPLE as that!