SOLUTION: A speculator sold some shares of stock worth $2880. Several days later, the stock having dropped in price $2 per share, he repurchased, for the same amount of money, 6 more shares

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Question 1196591: A speculator sold some shares of stock worth $2880. Several days later, the stock having dropped in price $2 per share, he repurchased, for the same amount of money, 6 more shares than he sold. How many shares did he sell?
Found 3 solutions by ikleyn, MathTherapy, josgarithmetic:
Answer by ikleyn(52816) About Me  (Show Source):
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.
A speculator sold some shares of stock worth $2880. Several days later,
the stock having dropped in price $2 per share, he repurchased,
for the same amount of money, 6 more shares than he sold.
How many shares did he sell?
~~~~~~~~~~~~~

Let x be the number of shares he sold.

Then the number of shares he purchased was (x+6).


The selling price was  2880%2Fx  dollars per share.

The buying price was  2880%2F%28x%2B6%29%29  dollars per share.


According to the problem, 

    2880%2Fx - 2880%2F%28x%2B6%29 = 2  dollars per share.


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To solve the equation, multiply both sides by x*(x+6).  You will get then

    2880(x+6) - 2880x = 2x*(x+6)

    1440(x+6) - 1440x = x(x+6)

          1440*6      = x^2 + 6x

          x^2 + 6x - 8640 = 0

          (x-90)*(x+96) = 0.


The only positive root, which makes sense is x= 90.


So, the number of shares he sold was 90.     ANSWER


CHECK.  The selling price was  2880%2F90%29 = 32 dollars per share.

        The buying price was  1280%2F%2890%2B6%29 = 30 dollars per share.

        The difference in prices was  32 - 30 = 2 dollars per share.   ! Correct !

Solved.



Answer by MathTherapy(10555) About Me  (Show Source):
You can put this solution on YOUR website!
A speculator sold some shares of stock worth $2880. Several days later, the stock having dropped in price $2 per share, he repurchased, for the same amount of money, 6 more shares than he sold. How many shares did he sell?
Let the number of shares sold be S
Then sale price per share = %222%2C880%22%2FS
With 6 more shares being repurchased than were sold (S + 6), price per share, upon repurchase = %222%2C880%22%2F%28S+%2B+6%29
We then get the following PRICE-PER-SHARE equation: matrix%281%2C3%2C+%222%2C880%22%2FS%2C+%22=%22%2C+2+%2B+%222%2C880%22%2F%28S+%2B+6%29%29
                                                    matrix%281%2C3%2C+%221%2C440%22%2FS%2C+%22=%22%2C+1+%2B+%221%2C440%22%2F%28S+%2B+6%29%29 ------ Factoring out GCF, 2, in numerator
                                     
                                    S(S + 96) - 90(S + 96) = 0
                                                  (S - 90) = 0        or        S + 96 = 0
                              Number of shares sold, or highlight_green%28matrix%281%2C3%2C+S%2C+%22=%22%2C+90%29%29     or        S = - 96 (ignore)

Answer by josgarithmetic(39621) About Me  (Show Source):
You can put this solution on YOUR website!
                  PRICE         QUANTITY           VALUE

SELL               p             n                 2880

REBUY              p-2           n+6               2880


To do tabulated data more simply

                PRICE             QTY.           VALUE

SELL           2880/n             n              2880

REBUY          2880/(n+6)        n+6             2880

DIFFERENCE        2

2880%2Fn-2880%2F%28n%2B6%29=2
Simplify and solve for n.