SOLUTION: An urn contains 9 red marbles, 10 white marbles, and 5 blue marbles marbles. A child randomly selects three (without replacement) from the urn. Round to four decimal places. Find t

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Question 1196586: An urn contains 9 red marbles, 10 white marbles, and 5 blue marbles marbles. A child randomly selects three (without replacement) from the urn. Round to four decimal places. Find the probability all three marbles are the same color
Answer by ikleyn(52777) About Me  (Show Source):
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An urn contains 9 red marbles, 10 white marbles, and 5 blue marbles highlight%28cross%28marbles%29%29.
A child randomly selects three (without replacement) from the urn.
Round to four decimal places. Find the probability all three marbles are the same color
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In all, there are 9 + 10 + 5 = 24 marbles 


The number of all possible triples is  C%5B24%5D%5E3 = 2024.

The number of all possible red   triples is  C%5B9%5D%5E3 = 84.

The number of all possible white triples is  C%5B10%5D%5E3 = 120.

The number of all possible blue triples is  C%5B5%5D%5E3 = 10.


The number of all favorable choices is the sum  84 + 120 + 10 = 214.



The probability under the problem's question is  


    P = favorable_triples%2Ftotal_triples = 214%2F2024 = 0.1057  (rounded).    ANSWER

Solved.