SOLUTION: A rectangular storage container with an open top is to have a volume of 10m cubed. The length of the base of the container is twice its width. Assume that the width of the base of

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Question 1196504: A rectangular storage container with an open top is to have a volume of 10m cubed. The length of the base of the container is twice its width. Assume that the width of the base of the container is x metres and the height is y metres. Assume that material costs $15 per square metre, while material for the side costs $20 per square metre.
Find an equation to express the volume of the container in terms of the variables X, and then write Y in terms of X.
My notes so far...
base width=X
base length=2X
height= 1.33X
I am lost.
If I can figure out the first part, then the following two parts of the question will become easier.
Found 2 solutions by MathLover1, math_tutor2020:
Answer by MathLover1(20855) About Me  (Show Source):
You can put this solution on YOUR website!

first part:
the width is x, length of the base is 2x , the base area is 2x%5E2
since the height is y meters, and the volume is:

V=2x%5E2%2Ay...........given V=10m%5E3
10m%5E3=2x%5E2%2Ay
y=10m%5E3%2F2x%5E2
y=5m%5E3%2Fx%5E2

Answer by math_tutor2020(3838) About Me  (Show Source):
You can put this solution on YOUR website!

A bit of commentary on @MathLover1's answer.

It's correct, but I would leave out the m%5E3 part
The m refers to meters, and it is NOT a variable.
The m%5E3 refers to cubic meters. Think of a 1 m by 1 m by 1 m cube.

I would write it as 10+=+2x%5E2y which solves to y+=+%285%29%2F%28x%5E2%29