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ANSWER. k! = 1*2*3* . . . *(k-1)*k.
Explanation.
Let the sets be A and B: they have equal numbers of elements.
1st element of A can be related to any of k elements of B.
2nd element of A can be related to any of remaining (k-1) elements of B.
3rd element of A can be related to any of remaining (k-2) elements of B.
. . . and so on . . .
It gives the answer.
Solved and explained.
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The problem is the same as to ask
" how many are there permutations of a set of k elements ? "