SOLUTION: Lotteries The Sad State Lottery requires you to select a sequence of four different numbers from 0 through 68. (Order is important.) You are a Winner if your sequence agrees with

Algebra ->  Probability-and-statistics -> SOLUTION: Lotteries The Sad State Lottery requires you to select a sequence of four different numbers from 0 through 68. (Order is important.) You are a Winner if your sequence agrees with      Log On


   



Question 1196229: Lotteries The Sad State Lottery requires you to select a sequence of four different numbers from 0 through 68. (Order is important.) You are a Winner if your sequence agrees with that in the drawing, and you are a Booby Prize Winner if your selection of numbers is correct, but in the wrong order. What is the probability of being a Winner? (Enter your probabilities as fractions.)
What is the probability of being a Booby Prize Winner?
What is the probability that you are either a Winner or a Booby Prize Winner?

Answer by ikleyn(52908) About Me  (Show Source):
You can put this solution on YOUR website!
Lotteries The Sad State Lottery requires you to select a sequence of four different numbers
from 0 through 68. (Order is important.)
You are a Winner if your sequence agrees with that in the drawing,
and you are a Booby Prize Winner if your selection of numbers is correct, but in the wrong order.
(a) What is the probability of being a Winner? (Enter your probabilities as fractions.)
(b) What is the probability of being a Booby Prize Winner?
(c) What is the probability that you are either a Winner or a Booby Prize Winner?
~~~~~~~~~~~~~~~~~~

(a)  In all, there are 69 numbers, from which the organizers of the lottery select 4 numbers.


     There are 69*68*67*66 = 20748024 different ORDERED sequences of 4 numbers from 69 numbers,
     that you may have on your ticket, so the number of tickets in the lottery is 20748024,
     and only one of them is a Winner.

     Therefore, the probability to be a Winner, having one ticket, is  P = 1%2F20748024.    ANSWER to (a)



(b)  The number of "happy" tickets for to be a Booby Prize Winner is  4! -1 = 1*2*3*4 - 1 = 24 - 1 = 23
        (permutations of 4 happy numbers minus one Winner ticket)


    Therefore, the probability to be a Booby Prize Winner, having one ticket, is  

        P = 23%2F20748024 = 1%2F902088.    ANSWER to (b)



(c)  The probability to be either-or in this case is  24%2F20748024 = 1%2F864501.   ANSWER to (c)

Solved.