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I will read the problem in this way
Find the exact value of arcsin(1/8) + arccos(1/8).
Solution
Use the fact that for any real value of x in the interval [0,1]
arcsin(x) + arccos(x) =
Which is clear from consideration of a right angled triangle with the hypotenuse of 1 and one leg of x.
In particular, for x = 1/8 we have
arcsin(1/8) + arccos(1/8) =
. ANSWER
Solved and thoroughly explained.