SOLUTION: Margin of Profit The margin of profit of a company is the net income divided by the total sales. A company's margin of profit increased by 0.02 from last year. Last year the compan

Algebra ->  Inequalities -> SOLUTION: Margin of Profit The margin of profit of a company is the net income divided by the total sales. A company's margin of profit increased by 0.02 from last year. Last year the compan      Log On


   



Question 1196129: Margin of Profit The margin of profit of a company is the net income divided by the total sales. A company's margin of profit increased by 0.02 from last year. Last year the company sold its product at $3.00 each and had a net income of $4500. This year it increased the price of its product by $0.50 each, sold 2000 more, and had a net income of $7140. The company never has had a margin of profit greater than 0.15. How many of its product were sold last year and how many were sold this year?

Found 2 solutions by ikleyn, math_tutor2020:
Answer by ikleyn(52754) About Me  (Show Source):
You can put this solution on YOUR website!
.
Margin of Profit
The margin of profit of a company is the net income divided by the total sales.
[1] A company's margin of profit increased by 0.02 from last year.
[2] Last year the company sold its product at $3.00 each and had a net income of $4500.
[3] This year it increased the price of its product by $0.50 each, sold 2000 more,
and had a net income of $7140.
[4] The company never has had a margin of profit greater than 0.15.
How many of its product were sold last year and how many were sold this year?
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            I numbered the sentences for easy referring.


Let x be the number of their product that were sold last year.


From [2], we have  this expression for margin profit last year 

    4500%2F%283x%29,  or  1500%2Fx.            (1)


From [3], we have  this expression for margin profit this year 

    7140%2F%283.50%2A%28x%2B2000%29%29,  or  2040%2F%28x%2B2000%29    (2)


From [1], quantity (2) is 0.02 greater than quantity (1).  It gives this equation

    2040%2F%28x%2B2000%29 - 1500%2Fx = 0.02.


    +-------------------------------------------------------------------+
    |    In this problem, the MAJOR STEP is to get a setup equation,    |
    |            and we successfully overcome it (!)                    |
    +-------------------------------------------------------------------+

           +---------------------------------------+
           |   To solve it is just a brute force.  |
           +---------------------------------------+



Multiply both sides by x*(x+2000)

    2040x - 1500(x + 2000) = 0.02x*(x+2000)


Simplify step by step

    2040x - 1500x - 3000000 = 0.02x^2 + 40x

    x^2 + 500x - 3000000 = 0

    (x-1500)*(x+2000) = 0


So, the rots are 1500 and -2000.  We reject the negative root,

and accept the positive one  x= 1500.


Thus last year the company sold 1500 units of the product.

This year they sold 2000 units more, i.e.  1500 + 2000 = 3500 units of the product.

Solved.

I'd say it is a good problem of a university Olympiad level for students of Finance department (without any joke).


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Thanks to tutor @math_tutor2020 for correcting me !



Answer by math_tutor2020(3816) About Me  (Show Source):
You can put this solution on YOUR website!

The tutor @ikleyn has the right idea, but made an error when going from
2040x - 1500x - 3,000,000 = 0.02x^2 + 40x
to
x^2 + 500x - 3,000,000 = 0

This is how I would continue the steps to solve for x
2040x - 1500x - 3,000,000 = 0.02x^2 + 40x
2040x - 1500x - 3,000,000 - 0.02x^2 - 40x = 0
-0.02x^2 + 500x - 3,000,000 = 0

Now apply the quadratic formula with
a = -0.02
b = 500
c = -3,000,000
x+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29

x+=+%28-500%2B-sqrt%28%28500%29%5E2-4%28-0.02%29%28-3000000%29%29%29%2F%282%28-0.02%29%29

x+=+%28-500%2B-sqrt%2810000%29%29%2F%28-0.04%29

x+=+%28-500%2B-++100%29%2F%28-0.04%29

x+=+%28-500%2B100%29%2F%28-0.04%29 or x+=+%28-500-100%29%2F%28-0.04%29

x+=+%28-400%29%2F%28-0.04%29 or x+=+%28-600%29%2F%28-0.04%29

x+=+10000 or x+=+15000

The two potential answers are
x = 10,000
x = 15,000

However we need to check them both

Let's check x = 10,000 first
If 10,000 units were sold last year, at $3 each, then the company earns 3*10,000 = 30,000 dollars in sales
Divide the net income for last year (4500) over the sales (30,000) and we'll get the profit margin for last year
margin = (4500)/(30,000) = 0.15
The profit margin for last year is 0.15, ie 15% of sales is net income
However, we've hit the ceiling since it states "The company never has had a margin of profit greater than 0.15"
So there's no way to have a profit margin increase of 0.02 to get to 0.15+0.02 = 0.17 for this current year.
Therefore, the value x = 10,000 is not a solution.


Now check x = 15,000
last year's sales = 15,000*3 = 45,000
last year profit margin = (net income)/(sales) = 4500/(45,000) = 0.10
The profit margin for last year was 0.10
So far so good since we're not at the ceiling of 0.15
this year's sales = (15,000+2,000)*(3+0.50) = 17,000*3.50 = 59,500
this years profit margin = (7140)/(59500) = 0.12 which is 0.02 more than 0.10
This confirms that x = 15,000 works as a solution


Answers:
15,000 units sold last year
17,000 units sold this year