SOLUTION: From a bag containing 5 nickels, 8 dimes, and 7 quarters, 5 coins are drawn at random and all at once. What is the probability of getting 2 nickels, 2 dimes, and 1 quarter? 1)Ho

Algebra ->  Probability-and-statistics -> SOLUTION: From a bag containing 5 nickels, 8 dimes, and 7 quarters, 5 coins are drawn at random and all at once. What is the probability of getting 2 nickels, 2 dimes, and 1 quarter? 1)Ho      Log On


   

Question 1196111: From a bag containing 5 nickels, 8 dimes, and 7 quarters, 5 coins are drawn at random and all at once. What is the probability of getting 2 nickels, 2 dimes, and 1 quarter?
1)How many ways can the desired selection be made?
2)How many total selections are possible?
3)What is the probability of making the desired selection?
Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


Using the basic definition of "n choose r"....

(1) Choose 2 of the 5 nickels AND 2 of the 8 dimes AND 1 of the 7 quarters:

C%285%2C2%29%2AC%288%2C2%29%2AC%287%2C1%29=10%2A28%2A7=1960

(2) Choose any 5 of the 5+8+7=20 coins:

C%2820%2C5%29=15504

(3) Using the basic definition of probability:

1960%2F15504

Simplify the fraction or convert to a decimal or percent as needed....