Question 1196099: Find 5-digit number
abcde = number
a=b+2
b=c+2
d=2d/2
e=2d/4
Found 2 solutions by josgarithmetic, greenestamps:
Answer by josgarithmetic(39620)   (Show Source):
You can put this solution on YOUR website! -------------------------
abcde = number
a=b+2
b=c+2
d=2d/2
e=2d/4
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Notice how the given facts also mean that d=d, which is redundant, and that  . This is the same as  ; and therefore some possible choices of d should be exactly one of 2, 4, 6, 8.
a must not be 0. If it were, then cannot have the five-digit number.
a may be exactly one of 1, 2, 3, 4, 5, 6, 7.
This not a finished solution; only some thoughts on the way to a solution.
Answer by greenestamps(13200)  (Show Source):
You can put this solution on YOUR website!
The problem as posted has a large number of solutions. I suspect the information is not shown correctly.
(1) a=b+2 and b=c+2 together mean the first three digits of the number are one of these:
420, 531, 642, 753, 864, or 975
That's 6 choices for the first three digits.
(2) d=2d/2 tells us nothing; e=2d/4=d/2d tells us that d is even. So d can be any even digit and e is half of d. So the last two digits are one of these:
00, 21, 42, 63, or 84
That's 5 choices for the last two digits.
With the problem as shown, there are 6*5=30 5-digit numbers that satisfy the given conditions.
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