SOLUTION: 1. A shopkeeper buys a certain number of bottles of mayonnaise for R100, she sells all except for ten of them which broke while being unpacked, making a profit of R50.00 If she so
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Question 1196061: 1. A shopkeeper buys a certain number of bottles of mayonnaise for R100, she sells all except for ten of them which broke while being unpacked, making a profit of R50.00 If she sold each bottle R10.oo more than she originally paid for it
1.1. How much did he pay for one bottle?
1.2. how much did he sell each Found 2 solutions by ikleyn, MathTherapy:Answer by ikleyn(52775) (Show Source):
You can put this solution on YOUR website! .
A shopkeeper buys a certain number of bottles of mayonnaise for R100, .
She sells all except for ten of them which broke while being unpacked,
making a profit of R50.00 If she sold each bottle R10.00 more than she originally paid for it
1.1. How much did she pay for one bottle?
1.2. how much did she sell each
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Let n be the number of bottles she bought for R100.
Then the price she paid for each single bottle was .
She sold (n-10) bottles for R100 + R50 = R150, in total.
The price she sold each bottle was .
The difference between prices was R10
- = 10.
The setup is done.
To solve this equation, multiply both sides by n*(n-10), then simplify
150n - 100*(n-10) = 10n*(n-10)
150n - 100n + 1000 = 10n^2 - 100n
10n^2 - 150n - 1000 = 0
n^2 - 15n - 100 = 0
(n-20)*(n+5) = 0.
Of two roots, 20 and -5, we select positive value n=20 for the number of bottles that she bought.
Then the price at which she bought each bottle was 100/20 = R5. ANSWER
The price at which she sold each bottle was R5 + R10 = R15. ANSWER
You can put this solution on YOUR website! 1. A shopkeeper buys a certain number of bottles of mayonnaise for R100, she sells all except for ten of them which broke while being unpacked, making a profit of R50.00 If she sold each bottle R10.oo more than she originally paid for it
1.1. How much did he pay for one bottle?
1.2. how much did he sell each
Let C be the cost of each bottle purchased
Then # of bottles purchased =
Also, # of bottles sold would be: , and sale price of each bottle = C + 10
We then get: ------ Multiplying by LCD, C
0 = (C - 5)(C + 20)
0 = C - 5 or 0 = C + 20
Cost of each bottle purchased or or C = - 20 (ignore)
Sale price of each bottle: C + 10 = 5 + 10 = R15.
