SOLUTION: Rewrite square root of negative 9 end root minus 6 in complex number notation.

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Question 1195879: Rewrite square root of negative 9 end root minus 6 in complex number notation.
Found 2 solutions by Alan3354, math_tutor2020:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Rewrite square root of negative 9 end root minus 6 in complex number notation.
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sqrt%28-9%29+-+6
= -6+%2B+3i
= -6+-+3i

Answer by math_tutor2020(3817) About Me  (Show Source):
You can put this solution on YOUR website!

Recall that i+=+sqrt%28-1%29 by definition of what it means to be an imaginary number.

So,
sqrt%28-9%29+=+sqrt%28-1%2A9%29

sqrt%28-9%29+=+sqrt%28-1%29%2Asqrt%289%29

sqrt%28-9%29+=+i%2A3

sqrt%28-9%29+=+3i
We do not involve the plus/minus in this case. This is because the result of the square root function is one output only.
Input = -9 leads to output = 3i

Therefore,
sqrt%28-9%29+-+6+=+3i+-+6+=+-6%2B3i
The complex number is of the form a+bi
a = -6 = real part
b = 3 = imaginary part