SOLUTION: The height of a {{{highlight(cross(rectangle))}}} <U>rectangular</U> {{{highlight(window)}}} is 0.4 m more than the width. The total area is 10.4 m2.
Determine the dimensions of
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-> SOLUTION: The height of a {{{highlight(cross(rectangle))}}} <U>rectangular</U> {{{highlight(window)}}} is 0.4 m more than the width. The total area is 10.4 m2.
Determine the dimensions of
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Question 1195545: The height of a rectangular is 0.4 m more than the width. The total area is 10.4 m2.
Determine the dimensions of the window by solving an appropriate equation. Round your answer to the nearest hundredth Answer by ikleyn(52915) (Show Source):
W*(W+0.4) = 10.4
W^2 + 0.4W - 10.4 = 0
Solve this quadratic equation using the quadratic formula.
ANSWER. The width W is 3.03 m; The height is 3.03+0.4 = 3.43 m.
CHECK. 3.03*3.43 = 10.394 m^2, which is good, taking rounding into account.
