SOLUTION: HIGHLIGHT ANSWER PLEASE
A town's population has been growing linearly. In 2003, the population was 59,800 people, and the population has been growing by approximately 3,600
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A town's population has been growing linearly. In 2003, the population was 59,800 people, and the population has been growing by approximately 3,600
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A town's population has been growing linearly. In 2003, the population was 59,800 people, and the population has been growing by approximately 3,600 people each year.
Write the formula for the function
P
(
x
)
which represents the population of this town
x
years after 2003.
P
(
x
)
=
Use this function to determine the population of this town in the year 2015.
In 2015, the population will be
people. Found 2 solutions by Theo, ikleyn:Answer by Theo(13342) (Show Source):
You can put this solution on YOUR website! straight line equation is y = mx + b
m is the slope
b is the y-intercept.
your equation becomes y = 3600 * x + 59800.
x = 0 is the year 2003.
when x = 0, y = 59800.
when x = 1, y = 59800 + 3500
when x = 2, y = 59800 + 2 * 3500
etc.
the year 2015 is 2015 - 2003 = 12 years after 2003.
the value of x in 2015 is equal to 12.
the value of y in 2015 is equal to 59800 + 12 * 3500 = 101800.
your solutions are:
the equation is y = 3500 * x + 59800 *****
the population in 2015 = 101800 *****
here is a graph of the equation.
let me know if you have any questions.
theo
