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Question 1195448: Clifford had 80% fewer sweets than Ashwin. After Ashwin gave 210 sweets to Clifford, Clifford had 2/3 as many sweets as Ashwin. How many sweets did each of them have in the end?
(a) Ashwin
(b) Clifford
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39790)   (Show Source):
You can put this solution on YOUR website! Clifford and Ashwin
w, the amount Ashwin started with.
80% of w is  .
Clifford started with  .
That is just for a beginning; one possible way. This here is not any finished solution.
Answer by MathTherapy(10801)  (Show Source):
You can put this solution on YOUR website!
Clifford had 80% fewer sweets than Ashwin. After Ashwin gave 210 sweets to Clifford, Clifford had 2/3 as many sweets as Ashwin. How many sweets did each of them have in the end?
(a) Ashwin
(b) Clifford
***************
Let amount Ashwin started with, be A
Since "Clifford had 80% fewer sweets than Ashwin," then Clifford started with (1 - 80%) of A, or .2A
When Ashwin gave 210 sweets to Clifford, Ashwin had A - 210 left
After receiving 210 from Ashwin, Clifford ended up with .2A + 210
With Clifford ending up with  as many sweets as Ashwin, we get the following FINAL-COUNT equation:
2(A - 210) = .6A + 630 -- Multiplying by LCD, 3
2A - 420 = .6A + 630
2A - .6A = 630 + 420
1.4A = 1,050
Number of sweets Ashwin started with, or 
Number of sweets Clifford started with: .2A = .2(750) = 150
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