SOLUTION: Suppose events A, B, and C are independent and P(A) = 1/4, P(B) = 1/5, P(C) = 1/8 Find the probability. (Enter the probability as a fraction.) P[(A ∪ B) ∩ C]

Algebra ->  Probability-and-statistics -> SOLUTION: Suppose events A, B, and C are independent and P(A) = 1/4, P(B) = 1/5, P(C) = 1/8 Find the probability. (Enter the probability as a fraction.) P[(A ∪ B) ∩ C]       Log On


   



Question 1195432: Suppose events A, B, and C are independent and
P(A) = 1/4, P(B) = 1/5, P(C) = 1/8
Find the probability. (Enter the probability as a fraction.)
P[(A ∪ B) ∩ C]

Answer by ikleyn(52867) About Me  (Show Source):
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Suppose events A, B, and C are independent and
P(A) = 1/4, P(B) = 1/5, P(C) = 1/8
Find the probability. (Enter the probability as a fraction.)
P[(A ∪ B) ∩ C]
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P(A U B) = P(A) + P(B) - P(A ∩ B) = 1%2F4%29 + 1%2F5 - %281%2F4%29%2A%281%2F5%29 = 5%2F20+%2B+4%2F20+-+1%2F20 = 8%2F20 = 2%2F5.


Next, since A, B and C are independent events, the events (A U B) and C are independent events, too.


Therefore,  P((A U B) ∩ C) = P(A U B) * P(C) = %282%2F5%29%2A%281%2F8%29 = 1%2F20.    ANSWER

Solved.