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Suppose a die is rolled twice and let
B = {first toss is a 1} D = {second toss is a 1}
Find the requested probability. (Enter the probability as a fraction.)
P(B ∪ D)
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(B U D) means "B or D".
It is very well known fact that P(B) = 1/6, P(D) = 1/6, P(B ∩ D) = 1/36.
Next, use the formula for the probability of the union of two events
P(B U D) = P(B) + P(D) - P(B ∩ D) = 1/6 + 1/6 - 1/36 = 6/36 + 6/36 - 1/36 = 11/36.
ANSWER. P(B U D) = 11/36.
Solved.
