SOLUTION: Hello, again. I hope I’m remembering this question as it appeared on my test. Two men leave from point A. The first man heads east at a rate of 20mph. The second man, leaving

Algebra ->  Vectors -> SOLUTION: Hello, again. I hope I’m remembering this question as it appeared on my test. Two men leave from point A. The first man heads east at a rate of 20mph. The second man, leaving      Log On


   



Question 1195365: Hello, again. I hope I’m remembering this question as it appeared on my test.
Two men leave from point A. The first man heads east at a rate of 20mph. The second man, leaving 30 minutes after the first man, heads south at a rate of 10Mph. What is their total distance apart after 2hours?
Thanks again!

Answer by ikleyn(52786) About Me  (Show Source):
You can put this solution on YOUR website!
.
Hello, again. I hope I’m remembering this question as it appeared on my test.
Two men leave from point A. The first man heads east at a rate of 20mph.
The second man, leaving 30 minutes after the first man, heads south at a rate of 10Mph.
What is their total distance apart after 2hours?
Thanks again!
~~~~~~~~~~~~~~~~~~

First man traveled 20 mph * 2 hours = 40 miles East.


Second man traveled 10 mph * 1.5 hours = 15 miles South.


To find the distance, use the Pythagoras


    distance = sqrt%2840%5E2+%2B+15%5E2%29 = 42.72 miles.    ANSWER

Solved and thoroughly explained.