SOLUTION: pleas help me id really apreciate it. the direction for the problem is to simplfy the equation x-4 over x squared + 3x divide by x squared - 3x -4 over 2x squared +6x please h

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: pleas help me id really apreciate it. the direction for the problem is to simplfy the equation x-4 over x squared + 3x divide by x squared - 3x -4 over 2x squared +6x please h      Log On


   



Question 119533: pleas help me id really apreciate it.
the direction for the problem is to simplfy the equation
x-4 over x squared + 3x divide by x squared - 3x -4 over 2x squared +6x
please help:)

Found 2 solutions by stanbon, Denean:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!

x-4 divide by x(squared)-3x-4
x(squared) +3x 2x (squared)+ 6x
---------------
Factor where you can to get:
[(x-4)/(x(x+3)] / [(x-4)(x+1)/2x(x+3)]
Cancel (x-4), x, (x+3) leaving you with:
=[1/1]/[(x+1)/2]
Invert the denominator and multiply to get:
= 2/(x+1)
======================
Cheers,
Stan H.

Answer by Denean(2) About Me  (Show Source):
You can put this solution on YOUR website!
%28%28x-4%29%2Fx%5E2%29%2B%28%283x%29%2Fx%5E2%29-%28%283x-4%29%2F2x%5E2%29%2B6x
First, you need to understand this is a fraction problem. You need to make all the fractions like. That means the denominators should all be the same. The first two terms' denominators are x^2 or x squared while the third term is 2x^2 or two x squared and the fourth term is 1. You would have to multiply the first and second term by 2 and the fourth term by 2x^2 to make the fractions like.
After making the fractions like, the problem should read like this:

Now add the numerators:
2x-8%2B6x-3x-4%2B12x%5E3
You can also rearrange it:
12x%5E3%2B2x%2B6x-3x-8-4
The numerators should add up to be:
%2812x%5E3%29%2B%285x%29-12
That fraction answer is:
%28%2812x%5E3%29%2B%285x%29-12%29%2F2x%5E2
To simplify the problem, divide every term by 2:
%28%286x%5E3%29%2B%285%2F2x%29-6%29%2Fx%5E2
This should be the right answer! Thank you for the stimulating problem!