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How much would you need to deposit in an account now in order to have $3000 
in the account in 10 years? 
Assume the account earns 3% interest compounded monthly.
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Use the formula for discretely compounded account 
      f = p * (1 + r) ^ n
where f is the future value
      p is the principal (the deposited amount)
      r is the interest rate per time period, presented as a decimal
      n is the number of time periods.
Your time periods are months.
f = 3000.
r = 0.03/12.
n = 10 years * 12 = 120 months.
Formula becomes 3000 =  ,  which gives
    p =
,  which gives
    p =  = 2223.29  to the nearest cent.    ANSWER
 = 2223.29  to the nearest cent.    ANSWER
Solved.
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To see many other similar  (and different)  solved problems on compounded interest accounts,  look into the lesson
    - Compounded interest percentage problems 
in this site.
Learn the subject from there.