SOLUTION: The total amount of registration fees paid by participants at a conference was $12,400 each participant who registered on the day of the conference paid a $150 fee and each partici

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Question 1195185: The total amount of registration fees paid by participants at a conference was $12,400 each participant who registered on the day of the conference paid a $150 fee and each participant who registered in advance paid a $125 fee. If 74 participants registered in advance, how many participants registered on the day of the conference?  

Found 3 solutions by math_tutor2020, ikleyn, josgarithmetic:
Answer by math_tutor2020(3817) About Me  (Show Source):
You can put this solution on YOUR website!

x = number of people who registered on the day of the conference

150x = amount of money made from the people registering on the day of the conference, at $150 each

74 people registered in advance. They each paid $125. So in total this subgroup paid 74*125 = $9250

150x+9250 = total amount of money from both groups combined
150x+9250 = 12400

Solve for x
150x+9250 = 12400
150x+9250-9250 = 12400-9250
150x = 3150
150x/150 = 3150/150
x = 21

Answer: 21 people

Answer by ikleyn(52848) About Me  (Show Source):
You can put this solution on YOUR website!
.

It can be solved in one line

    how many participants registered on the day of the conference = %2812400-74%2A125%29%2F150 = 21.    ANSWER


The formula is OBVIOUS and self-explanatory.

It is how my teachers touch me to solve such problems in my 4-th grade,
without making any equations.



Answer by josgarithmetic(39625) About Me  (Show Source):
You can put this solution on YOUR website!
a, how many advanced payers
d, how many on the day of conf
a=74;
125%2A74%2B150%2Ad=12400

150d=12400-125%2A74
d=%2812400-125%2A74%29%2F150-------compute this.