SOLUTION: Rock puts $1000 in the bank for two years at 10% interest compounded annually. At the end of the two years, what will be her balance?

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Question 1195149: Rock puts $1000 in the bank for two years at 10% interest compounded annually. At the end of the two years, what will be her balance?
Found 2 solutions by MathLover1, ikleyn:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

A+=+P%281+%2B+r%2Fn%29%5E%28nt%29

given:
P=1000
t=2 years
R=5%
n=1
First, convert rate R as a percent to r as a decimal
r+=+R%2F100
r+=+5%2F100
r+=+0.05 rate per year,
Then solve the equation for A
A+=+P%281+%2B+r%2Fn%29%5E%28nt%29%0D%0A%7B%7B%7BA+=+1000.00%281+%2B+0.05%2F1%29%281%2A2%29
A+=+1000.00%281+%2B+0.05%29%282%29
A+=+1102.50
after two years, her balance will be +1102.50


Answer by ikleyn(52788) About Me  (Show Source):
You can put this solution on YOUR website!
.
Rock puts $1000 in the bank for two years at 10% interest compounded annually.
At the end of the two years, what will be her balance?
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            @MathLover1 read, interpreted and solved the problem incorrectly,
            giving wrong answer.


As written, the text means that the interest is 10% annually, compounded annually.


So, after one year, the amount at the account is  1.1*1000 = 1100 dollars, after fisrt compounding.


After two years, the amount at the account is  1.1%5E2%2A1000 = 1.21*1000 = 1210 dollars, after second compounding.


ANSWER. After two years, the balance will be 1210 dollars.

Solved.

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To see many other similar  (and different)  solved problems on compounded interest accounts,  look into the lesson
    - Compounded interest percentage problems
in this site.


Learn the subject from there.