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The given BIGGEST rectangle has dimensions 2+6 = 8 units by 9+5 = 14 units.
If the left lover corner of this rectangle is (0,0), the origin, then OBVIOUSLY,
the center point of the rectangle is (7,4).
The area of the big rectangle is 8*14 square units, and 1/4 of its area is
= 28 square units.
OK. Let's consider the shaded quadrilateral.
Then it is OBVIOS that the area of the shaded quadrilateral is equal to 1/4 of the area
of the BIG rectangle plus the area of the adjacent "vertical" right-angled triangle
minus the area of the adjacent "horizontal" right angled triangle. (*)
Adjacent "vertical" triangle has the legs 8-4 = 4 units (vertical) and 9-7 = 2 units (horizontal);
so its area is (1/2)*4*2 = 4 square units.
Adjacent "horizontal" triangle has the legs 8-4-2 = 2 units (vertical) and 14-7 = 7 units (horizontal);
so its area is (1/2)*2*7 = 7 square units.
Therefore, the area of the shaded region, according to the wording formula (*) is
28 + 4 - 7 = 25 square units. ANSWER
Solved.
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Actually, to solve the problem, this three-steps simple instruction is enough:
(1) take one fourth of the area of the big rectangle;
(2) add the area of the adjacent "vertical" right-angled triangle;
(3) subtract the area of the adjacent "horizontal" right-angled triangle.