SOLUTION: Determine all the values where -3sinx=√3 cosx for 0 degrees less than an equal to x less than an equal to 360 degrees.
thank you so much
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thank you so much
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Question 1194997: Determine all the values where -3sinx=√3 cosx for 0 degrees less than an equal to x less than an equal to 360 degrees.
thank you so much Answer by ikleyn(52803) (Show Source):
You can put this solution on YOUR website! .
Determine all the values where -3*sinx = √3*cosx for 0 <= x < 360 degrees.
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I specially re-wrote your formulation in order for
you learn on how to do it in a right way.
Your original equation is
-3*sin(x) = .
Divide both sides by -3*cos(x). You will get an EQUIVALENT equation
tan(x) = .
In the given interval 0 <= x < 360 it has presicely two solutions
x = 150 degrees and x = 330 degrees. ANSWER
Solved.
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A person who loves accurate mathematical solutions, may ask me why I divided the original
equation by cos(x) without taking care that cos(x) can be equal to 0 (zero).
It is right question.
The answer is : it is because if cos(x) = 0, then due to the given equation, sin(x) = 0;
but sin(x) and cos(x) may not be equal to zero simultaneously.
So, the case cos(x) = 0 is EXCLUDED by the given equation ( ! )
