SOLUTION: In choosing what music to play at a charity fund raising event, Cory needs to have an equal number of symphonies from Haydn, Mendelssohn, and Mahler. If he is setting up a schedul

Algebra ->  Permutations -> SOLUTION: In choosing what music to play at a charity fund raising event, Cory needs to have an equal number of symphonies from Haydn, Mendelssohn, and Mahler. If he is setting up a schedul      Log On


   



Question 1194941: In choosing what music to play at a charity fund raising event, Cory needs to have an equal number of symphonies from Haydn, Mendelssohn, and Mahler. If he is setting up a schedule of the 12 symphonies to be played, and he has 104 Haydn, 17 Mendelssohn, and 9 Mahler symphonies from which to choose, how many different schedules are possible? Express your answer in scientific notation rounding to the hundredths place.
Answer by ikleyn(52792) About Me  (Show Source):
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In choosing what music to play at a charity fund raising event,
Cory needs to have an equal number of symphonies from Haydn, Mendelssohn, and Mahler.
If he is setting up a schedule of the 12 symphonies to be played,
and he has 104 Haydn, 17 Mendelssohn, and 9 Mahler symphonies from which to choose,
how many different schedules are possible?
Express your answer in scientific notation rounding to the hundredths place.
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Cory can choose 4 symphonies from 104 symphonies by Haydn in  C%5B104%5D%5E4 = 4598126 different ways.

Cory can choose 4 symphonies from 17 symphonies by Mendelssohn in  C%5B17%5D%5E4 = 2380 different ways.

Cory can choose 4 symphonies from 9 symphonies by Mahler in  C%5B9%5D%5E4 = 126 different ways.


So, Cory can combine  C%5B104%5D%5E4+%2A+C%5B17%5D%5E4+%2A+C%5B9%5D%5E4 = 4598126 * 2380 * 126 = 1378886024880

different sets of 12 symphonies taking 4 symphonies of each of the three famous composers.


    +-----------------------------------------------------------------------+
    |    But this number is not yet the number of all possible schedules.   |
    +-----------------------------------------------------------------------+


To get the number of all possible schedules, we should take every of these 1378886024880 sets

and make it a subject of all possible  12! = 12*11*10*9*8*7*6*5*4*3*2*1 = 479001600  permutations.



After this permutization of each of 1378886024880 sets, we get the total number of all possible schedules

    C%5B104%5D%5E4+%2A+C%5B17%5D%5E4+%2A+C%5B9%5D%5E4 * 12! = 1378886024880 * 479001600 = 6.60489%2A10%5E20 schedules.    


You can round this number to the requested form and get the  ANSWER :   there are  6.60%2A10%5E20  different possible schedules.

Solved.