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Question 1194914: Lucy paid a total of $550 for a brooch, a necklace and a watch. She spent 3/5 money on the brooch. The necklace cost 3 times as much as the watch. How much did she pay for the necklace?
Found 2 solutions by ikleyn, math_tutor2020:
Answer by ikleyn(52903)   (Show Source):
You can put this solution on YOUR website! .
Lucy paid a total of $550 for a brooch, a necklace and a watch.
She spent 3/5 money on the brooch. The necklace cost 3 times as much as the watch.
How much did she pay for the necklace?
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To simplify the problem, subtract the cost of the broch from $550.
The rest is 2/5 of $550, which is $220.
So, the necklace and the watch cost together $220, and the necklace costs 3 times as much as the watch.
From it, using your mental skills, you conclude that the necklace costs 3/4 of $220, or 3*55 = 165 dollars. ANSWER
Alternatively, if you rely more to equations than on your mental skills,
you can write x + 3x = 220 and solve it for x, which is the price for the watch.
Doing this way, you get that the watch costs x= 55 dollars and the necklace costs 3x = 3*55 = 165 dollars,
giving the same answer.
Solved.
Answer by math_tutor2020(3817)  (Show Source):
You can put this solution on YOUR website!
w = cost of the watch in dollars
3w = cost of the necklace (3 times as much as the watch)
w+3w = 4w = combined cost of the watch and necklace
Lucy spent $550 for the brooch, necklace, and watch.
She spent 3/5 of that total on the brooch alone.
(3/5)*550 = 330 dollars was spent on the brooch alone
The amount left over is 550-330 = 220
Set this equal to the 4w mentioned and solve for w.
4w = 220
w = 220/4
w = 55
The watch is $55
Necklace = 3w = 3*55 = 165
Answer: The necklace is $165
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