SOLUTION: Ben and Juan fought 4 timesdebate of which Ben wins 2, 1 is won by Juan and 1 ended in a draw. If they agree to have 3 more fight, find the probability that Ben and Juan win altern
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-> SOLUTION: Ben and Juan fought 4 timesdebate of which Ben wins 2, 1 is won by Juan and 1 ended in a draw. If they agree to have 3 more fight, find the probability that Ben and Juan win altern
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Question 1194861: Ben and Juan fought 4 timesdebate of which Ben wins 2, 1 is won by Juan and 1 ended in a draw. If they agree to have 3 more fight, find the probability that Ben and Juan win alternately. Answer by ikleyn(52794) (Show Source):
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Ben and Juan fought 4 timesdebate of which Ben wins 2, 1 is won by Juan and 1 ended in a draw.
If they agree to have 3 more fight, find the probability that Ben and Juan win alternately.
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How this problem is worded, it contradicts to the base framework
and the base conceptions of the probability theory.
