SOLUTION: Two urns contain 4 white and 6 black balls and 3 white and 8 black balls respectively. If one ball is drawn from each urn, find the probability that the balls drawn are of differen
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-> SOLUTION: Two urns contain 4 white and 6 black balls and 3 white and 8 black balls respectively. If one ball is drawn from each urn, find the probability that the balls drawn are of differen
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Question 1194860: Two urns contain 4 white and 6 black balls and 3 white and 8 black balls respectively. If one ball is drawn from each urn, find the probability that the balls drawn are of different colors? Answer by greenestamps(13196) (Show Source):
(1)
white, then black: (4/10)(8/11) = 32/110
black, then white: (6/10)(3/11) = 18/110
different: 32/110+18/110=50/110 = 5/11
(2) or
both white: (4/10)(3/11)=12/110
both black: (6/10)(8/11)=48/110
both the same: 12/110+48/110 = 60/110 = 6/11
different (NOT both the same): 1-6/11 = 5/11
Note: in performing probability calculations like this, don't simplify fractions until the final answer. Doing so will nearly always create more (unnecessary) work for you.
