SOLUTION: given the equation {{{y=-3(1/2)^X=2 +6}}} a) Graph the function using a suitable scale and any means at your disposal. b) Draw the secants from the y-intercept to each of the

Algebra ->  Trigonometry-basics -> SOLUTION: given the equation {{{y=-3(1/2)^X=2 +6}}} a) Graph the function using a suitable scale and any means at your disposal. b) Draw the secants from the y-intercept to each of the       Log On


   



Question 1194792: given the equation
y=-3%281%2F2%29%5EX=2+%2B6
a) Graph the function using a suitable scale and any
means at your disposal.
b) Draw the secants from the y-intercept to each of the
points on the curve ending at x = 2, 1, 0.5, 0.1, 0.01,
0.001.
c) Determine the equations of each of the secants
constructed in part b).
d) Determine the equation of the tangent at the
y-intercept in simplified form.
Determine the general equation of the secant from any
point (A,f(A)) to the point on f%28x%29+=+4 where x=2. Describe
how you would use this to find the equation of the tangent
at the point (2,f(2)).

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
given the equation
y=-3%281%2F2%29%5EX=2+%2B6
======================
y = 8
-----
-3(1/2)^x = 8
(1/2)^x = -8/3
No solution