SOLUTION: Good evening ma'am or sir will you please help on how to solve this problem involving expressions with exponents? Thank you very much. 4). An electric current of one (1) ampere

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Question 119477: Good evening ma'am or sir will you please help on how to solve this problem involving expressions with exponents? Thank you very much.
4). An electric current of one (1) ampere will deposit 0.0011180 g of silver each second from a water solution of silver nitrate. How many grams of silver will be deposited if the current is 1 * 10^-1 amperes and the time is one (1) hour and 20 minutes?
Thank you.
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
Use Faraday's equation for electrolysis is +m+=+k%2AI%2At
That is:

mass_+in_+grams+=+electrochemical_+equivalent+%2A+current+%2A+time
or
m+=+k+%2AI+%2A+t
where
m=+mass in grams

k=+electrochemical_+equivalent+……..atom weight divided by valence times 96,500; k for silver is 107.88+%2F96500 or = 0.001118

I=+current……………….. in amps

t=+time…………………….. in seconds

given:

k+=+0.001118

I=+1+%2A+10%5E-1+%2AA+……………….. in amps

t=+1+h+20+min+……………………..should be in seconds, and that will be
3600s+%2B1200s+=+4800s

So, we will have:

m+=+k+%2AI+%2A+t

m+=+0.001118+%2A10%5E-1++%2A+4800+

m+=+0.001118+%2A+1%2F10++%2A+4800+

m+=+0.001118+%2A+.1++%2A+4800+

m+=+0.53664g