SOLUTION: Consider a regular octagon with an apothem of length
a = 9.2 in. and each side of length
s = 7.6 in
Find the perimeter (in inches) of this regular octagon.
Find the area (in
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-> SOLUTION: Consider a regular octagon with an apothem of length
a = 9.2 in. and each side of length
s = 7.6 in
Find the perimeter (in inches) of this regular octagon.
Find the area (in
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Question 1194223: Consider a regular octagon with an apothem of length
a = 9.2 in. and each side of length
s = 7.6 in
Find the perimeter (in inches) of this regular octagon.
Find the area (in square inches) of this regular octagon. Answer by ikleyn(52786) (Show Source):
(1) The perimeter is 8 times the side length.
(2) The area is comprised of 8 (eight) isosceles congruent triangles with the common center.
Find the area of one (of each) such a triangle as half the product the side length by the apothem.
Then take this area 8 times.
Solved.
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Comment from student: so to get the area would it be 4.6*8=36.8?
My response : What is unclear to you in my solution and in my instruction ?
Simply read attentively and perform exactly as prescribed.