SOLUTION: A ball is thrown from an initial height of 4 feet with an initial upward velocity of 32 ft/s. The ball's height, h (in feet), after t seconds is given by the following h=4+32t-1

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: A ball is thrown from an initial height of 4 feet with an initial upward velocity of 32 ft/s. The ball's height, h (in feet), after t seconds is given by the following h=4+32t-1      Log On


   



Question 1194120: A ball is thrown from an initial height of 4 feet with an initial upward velocity of 32 ft/s. The ball's height, h (in feet), after t seconds is given by the following
h=4+32t-16t^2
Find ALL values of t for which the ball's height is 12 feet. Round your answer(s) to the nearest hundredth.

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
h=4+32t-16t^2 = 12
-16t%5E2+%2B+32t+-+8+=+0
Solve for t.