SOLUTION: hi can i get the anwser to both questions Two towns are 1050 miles apart. A group of hikers starts from each town and walks down the trail toward each other. They meet after a t

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: hi can i get the anwser to both questions Two towns are 1050 miles apart. A group of hikers starts from each town and walks down the trail toward each other. They meet after a t      Log On


   



Question 1194102: hi can i get the anwser to both questions
Two towns are 1050 miles apart. A group of hikers starts from each town and walks down the trail toward each other. They meet after a total hiking time of 200 hours. If one group travels 1 1/2 mile per hour slower than the other​ group, find the rate of each group.
slower group rate
faster group rate

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Two towns are 1050 miles apart. A group of hikers starts from each town and walks down the trail toward each other. They meet after a total hiking time of 200 hours. If one group travels 1 1/2 mile per hour slower than the other​ group, find the rate of each group.
================
Walking "toward each other" is going in opposite directions.
The speeds are added.
-----
The sum of their speeds is 1050/200 hours = 5.25 mi/hr
-------
Sum = 5.25
Difference = 1.5
------
F + S = 5.25
F - S = 1.5
================= Add