SOLUTION: How do I put this word problem into an equation? May rides her bike the same distance that leah walks. May rides her bike 10 km/h faster than leah walks. If it takes May 1 hour

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Question 119410: How do I put this word problem into an equation?
May rides her bike the same distance that leah walks. May rides her bike 10 km/h faster than leah walks. If it takes May 1 hour and Leah 3 hours to travel that distance, how fast does each travel?
I can figure the equation out, i just need help puting the word problem into a equation
Found 2 solutions by stanbon, josmiceli:
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
May rides her bike the same distance that leah walks. May rides her bike 10 km/h faster than leah walks. If it takes May 1 hour and Leah 3 hours to travel that distance, how fast does each travel?
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May DATA:
Time = 1 hr ; rate = x km/hr ; distance = 1x = x km
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Leah DATA:
Time = 3 hrs; rate = (x-10)km/hr ; distance = 3(x-10) = 3x-30 km
------------------------
EQUATION:
distance = distance
x = 3x-30
2x = 30
x = 15 km/hr (May's rate)
x-10 = 5 km/hr (Leah's rate)
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Cheers,
Stan H.

Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website!
You have two equations, and both are distance = rate x time.
May's equation:

Leah's equation:

Here is what is given:
km
km/hr
hr
hr
Now plug these givens into equations

and since ,

km/hr answer

km/hr answer
check answer

km

km

OK