SOLUTION: A hockey player scores on 18% of his shots.
a)What is the probability he will score for the first time on his fifth shot?
b)What is the probability that it will take him fewer th
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-> SOLUTION: A hockey player scores on 18% of his shots.
a)What is the probability he will score for the first time on his fifth shot?
b)What is the probability that it will take him fewer th
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Question 1194069: A hockey player scores on 18% of his shots.
a)What is the probability he will score for the first time on his fifth shot?
b)What is the probability that it will take him fewer than 3 shots to score?
c)How many shots should he expect to take before scoring?
You can put this solution on YOUR website! This would be 0.82^4*0.18=0.0814
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for the first shot it would be 0.18 probability to score
for the second shot it would be 0.82*0.18=0.1476, so the answer is the sum or 0.3276 probability
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the expected number of shots before scoring is 1/p=1/0.18, or 5.56
