Two consecutive even numbers are such that their sum is greater than 98 decreased by twice the larger. Find the smallest possible values for the integers.
x = smaller
x+2 = larger
their sum, x+(x+2), is greater than, >, 98 decreased by, -, twice the
larger, 2(x+2).
So:
x+(x+2) > 98-2(x+2)
x+x+2 > 98-2x-4
2x+2 > 94-2x
2x+2x > 94-2
4x > 92
x > 23
Since x is the smaller, it must be greater than 23,
and the larger, x+2, must be 25 or larger.
The smallest two such consecutive even integers are 24 and 26.
Edwin