SOLUTION: An object moves along a straight path at a speed v(t) = 2+4t-t2 of m/s. When will the object move at a maximum speed?
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An object moves along a straight path at a speed v(t) = 2+4t-t2 of m/s. When will the object move at a maximum speed?
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They want you determine at what time moment the given quadratic function is maximum.
This quadratic function represents a downward parabola. It is downward parabola, because the coefficient at t^2 is negative.
A downward parabola y = ax^ + bx + c with negative coefficient "a" has the maximum value at x = .
In your case. a = -1, b= 4, so the maximum is achieved at
t = = = 2 seconds.
It is the answer to the problem's question.
