SOLUTION: Out of six computer chips, two are defective. If two chips are randomly
chosen for testing (without replacement), compute the probability that
the first is defective but the se
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-> SOLUTION: Out of six computer chips, two are defective. If two chips are randomly
chosen for testing (without replacement), compute the probability that
the first is defective but the se
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Question 1193996: Out of six computer chips, two are defective. If two chips are randomly
chosen for testing (without replacement), compute the probability that
the first is defective but the second is not defective.
a. 0.067
b. 0.267
c. 0.933
d. 0.600 Answer by math_helper(2461) (Show Source):
2 defective
4 good
--
6 total
P(1st is defective) = 2/6
This leaves a total population of 5 from which the 2nd chip is selected:
P(2nd is not defective) = 4/5
P = (2/6)*(4/5) = 8/30 or approx. 0.267