SOLUTION: Past experience shows that 1% of the light bulbs produced in a plant are defective. Find the probability that more than one blub is defective in a random sample of 30 bulbs, using
Algebra ->
Probability-and-statistics
-> SOLUTION: Past experience shows that 1% of the light bulbs produced in a plant are defective. Find the probability that more than one blub is defective in a random sample of 30 bulbs, using
Log On
Question 1193994: Past experience shows that 1% of the light bulbs produced in a plant are defective. Find the probability that more than one blub is defective in a random sample of 30 bulbs, using (a) binomial distribution and (b)the poisson distribution Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! probability 1 bulb is defective is 30C1(0.01)^1*0.99^29=0.2242
probability 0 are defective is 0.99^30=0.7397
That sum is 0.9639
the complement probability of 0.0361 is the probability that more than one bulb is defective
-
using the Poisson distribution, np=lambda or 30*0.01 or 0.3
P(0)=e^(-0.3)=0.7408
P(1)=e^(-0.3)*0.3^1/1!
=0.2222
That sum is 0.9630, and the complement is 0.0370, the probability that more than one bulb is defective.
