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Question 1193934: The ratio of the number of marbles May, Teddy and Sam had was 3:5:2. During a game, May lost half of her marbles to Teddy. Teddy lost 20 marbles to Sam who then had 3 times the number of marbles May had at the end of the game.
(a) What was the percentage increase in the number of marbles Sam had at the end of the game?
(b) How many marbles did Teddy have at the end of the game?
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! The ratio of the number of marbles May, Teddy and Sam had was 3:5:2.
let x = the multiplier
then
3x = no of marbles May had
5x = no. Ted had
2x = no. Sam had
During a game, May lost half of her marbles to Teddy.
Now May had 1.5x marbles and Ted has 6.5x marbles
:
Teddy lost 20 marbles to Sam
(6.5x - 20) = Teds marbles
and
2x + 20 = Sam's marbles
who (Sam) then had 3 times the number of marbles May had at the end of the game.
(2x+20) = 3(1.5x)
2x + 20 = 4.5x
2x - 4.5x = -20
-2.5x = -20
x = -20/-2.5
x = 8 is the multiplier
therefore now
1.5(8) = 12 for May
6.5(8) - 20 = 32 for Ted
2(8) + 20 = 36 for Sam
:
(a) What was the percentage increase in the number of marbles Sam had at the end of the game?
Sam started with 2(8) = 16 and ended with 36. a 225% increase
:
(b) How many marbles did Teddy have at the end of the game? 32
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