SOLUTION: Find three consecutive whole numbers such that twice the sum of the two smallest numbers is 10 more than three times the largest number.

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Question 1193931: Find three consecutive whole numbers such that twice the sum of the two smallest numbers is 10 more than three times the largest number.
Answer by ikleyn(52787) About Me  (Show Source):
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Find three consecutive whole numbers such that twice the sum of the two smallest numbers
is 10 more than three times the largest number.
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Let the numbers be n, (n+1) and (n+2).


Write equation as you read the problem

    2*(n + (n+1)) = 3*(n+2) + 10.


Now simplify and find "n"

    2n + 2n + 2 = 3n + 6 + 10

    4n + 2 = 3n + 16

    4n - 3n = 16 - 2

       n    =    14


ANSWER.  The numbers are 14, 15 and 16.

Solved, answered and explained.