Question 1193889:  Find the quadratic function that fits the data points (1,6) (-1,2) and (3,34). 
 Found 3 solutions by  ankor@dixie-net.com, MathTherapy, Alan3354: Answer by ankor@dixie-net.com(22740)      (Show Source): 
You can  put this solution on YOUR website! Find the quadratic function that fits the data points (1,6) (-1,2) and (3,34). 
Using the form ax^2 + bx + c = y, write an equation for each x,y point 
1,6:  a + b + c = 6 
-1,2: a - b + c = 2 
3,34: 9a+3b + c = 34 
: 
add the 1st 2 equations 
 a + b + c = 6 
 a - b + c = 2 
--------------- 
2a + 0 + 2c = 8 
simplify, divide by 2 
a + c = 4 
: 
multiply the 2nd equation by 3, add to the 3rd equation 
3a - 3b + 3c = 6 
9a + 3b +  c = 34 
-------------------- 
12a + 0 + 4c = 40 
simplify, divide by 2 
6a + 2c = 20 
: 
Multiply (a+c=4) by 2, subtract from the above equation 
6a + 2c = 20 
2a + 2c = 8 
--------------subtraction eliminates c, find a 
4a + 0 = 12 
a = 12/4 
a = 3 
: 
a + c = 4 
3 + c = 4 
c = 1 
and 
a + b + c = 6 
3 + b + 1 = 6 
b = 6 - 4 
b = 2 
: 
The equation: y = 3x^2 + 2x + 1 
 
 Answer by MathTherapy(10557)      (Show Source): 
You can  put this solution on YOUR website! Find the quadratic function that fits the data points (1,6) (-1,2) and (3,34). 
Equation of a PARABOLA: y = ax2 + bx + c
                        6 = a(1)2 + b(1) + c ----- Substituting (1, 6) for (x, y) 
                        6 = a + b + c ---- eq (i)
                        y = ax2 + bx + c
                        2 = a(- 1)2 + b(- 1) + c ----- Substituting (- 1, 2) for (x, y) 
                        2 = a - b + c ---- eq (ii)
                        y = ax2 + bx + c
                       34 = a(3)2 + b(3) + c ----- Substituting (3, 34) for (x, y) 
                       34 = 9a + 3b + c ---- eq (iii)
                          6 = a + b + c ------ eq (i)
                          2 = a - b + c ------ eq (ii)
                         34 = 9a + 3b + c --- eq (iii)
                          4 = 2b ---- Subtracting eq (ii) from eq (i)
                          
                         32 = 8a + 4b ----- Subtracting eq (ii) from eq (iii) ---- eq (iv)
                         32 = 8a + 4(2) --- Substituting 2 for b in eq (iv)
                       
                          6 = 3 + 2 + c ---- Substituting 3 for a, and 2 for b in eq (i)
                          6 = 5 + c 
                          1 = c 
  Equation of a PARABOLA: y = ax2 + bx + c
                          y = 3x2 + 2x + 1 ------- Substituting 3 for a, 2 for b, and 1 for c 
 Answer by Alan3354(69443)      (Show Source): 
You can  put this solution on YOUR website! Find the quadratic function that fits the data points (1,6) (-1,2) and (3,34). 
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I have an Excel sheet that does that. 
Also circles. 
You want a copy? 
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