SOLUTION: Two bugs at the opposite ends of a 330-inch wire started crawling at each other at the same time. One bug was traveling 2 inches per second faster than the other. If the bugs meet
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Question 1193833: Two bugs at the opposite ends of a 330-inch wire started crawling at each other at the same time. One bug was traveling 2 inches per second faster than the other. If the bugs meet after 55 seconds, how fast was each bug traveling? Give an equation and solution. Found 2 solutions by ankor@dixie-net.com, ikleyn:Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Two bugs at the opposite ends of a 330-inch wire started crawling at each other at the same time.
One bug was traveling 2 inches per second faster than the other.
If the bugs meet after 55 seconds, how fast was each bug traveling?
Give an equation and solution.
:
Let s = speed in in/sec of the first bug
then
(s+2) = speed of the other bug
:
Write a dist equation; dist = time * speed
Both bugs travel for 55 sec
55s + 55(s+2) = 330
55s + 55s + 110 = 330
110s = 330 - 110
s = 220/110
s = 2 in/sec is the speed of the one bug
and
2+2 = 4 in/sec is speed of the faster bug
:
:
Check this find the actual dist each bug traveled
55(2) = 110 in
55(4) = 220 in
---------------
total dist: 330 in
You can put this solution on YOUR website! .
Two bugs at the opposite ends of a 330-inch wire started crawling at each other at the same time.
One bug was traveling 2 inches per second faster than the other.
If the bugs meet after 55 seconds, how fast was each bug traveling? Give an equation and solution.
~~~~~~~~~~~~~~~~
Let "r" be the rate of the slower bug, in inches per seconds.
Then the rate of the other bug is (r+2) inches per second.
The total distance equation is
55r + 55*(r+2) = 330 inces.
Simplify and find "r"
55r + 55r + 110 = 330
110r = 330 - 110
110r = 220
r = 220/110 = 2.
ANSWER. The rate of the slower bug is 2 inches per second; that of the faster bug is 2 + 2 = 4 inches per second.
