.
The space of events is the set of all pairs of the form (a,L), where "a" is an integer number from 1 to 6 and "L" is a letter H or T.
The number "a" represents the outcome of thrown the die, while the letter L represents the outcome of tossing coin.
So, the space of events has 6*2 = 12 elements with the probability of
each.
Thus, in case (a) the probability is P =
.
In case (b), the probability is 0 (zero), since the outcome "7" is impossible.
In case (c), the answer is
=
=
.
Solved.