SOLUTION: Given: rhombus ABCD (not shown) in which diagonals AC and DB intersect at point E DB = AB = 6 Find: AC simplest radical form AC = approximation AC =

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Question 1193624: Given:
rhombus ABCD (not shown) in which diagonals AC and DB intersect at point E
DB = AB = 6
Find: AC
simplest radical form AC =

approximation AC =

Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
Diagonals of rhombus bisect each other at right angles
In %28triangle%29+AEB+
AB=6 EB = 1/2 * DB =3
AB^2-EB^2= AE^2
6^2-3^2= 27
AE = 3sqrt%283%29
AC = 2* AE = 6sqrt%283%29
.