Question 1193497: Car A left town C for Town Y at 6:00am and travelled at an average speed of 80km/h. At 7.30am car B left town X for town Y. If car B travels at an average speed of 100km/h, at what time will it catch car A.
Found 2 solutions by ankor@dixie-net.com, ikleyn:
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! In order to make this make sense, change c to x
:
Car A left town X for Town Y at 6:00am and travelled at an average speed of 80km/h.
At 7.30am car B left town X for town Y.
If car B travels at an average speed of 100km/h, at what time will it catch car A.
:
let t = travel time of car A
Car B left 1.5 hrs later, therefore
(t-1.5) = travel time of car B
:
Write a dist equation, when Car B catches Car A, they will have traveled the same distance
dist = speed * time
B's dist = A's dist
100(t-1.5) = 80t
100t - 150 = 80t
100t - 80t = 150
20t = 150
t = 150/20
t = 7.5 hrs (7 hrs 30 min)
Find the actual time
6:00 + 7:30 = 13:30 which is 1:30 Pm
:
:
Check this, find the actual dist each traveled
6*100 = 600 km
7.5*80 = 600 km
Answer by ikleyn(52775)  (Show Source):
You can put this solution on YOUR website! .
Car A left town C for Town Y at 6:00am and travelled at an average speed of 80km/h.
At 7.30am car B left town X for town Y. If car B travels at an average speed of 100km/h,
at what time will it catch car A.
~~~~~~~~~~~~~~~~~
In this problem, the input info is incomplete.
It DOES NOT determine, where town X is located relative towns C and Y.
THEREFORE, the problem can not be solved.
 : the problem is FATALLY DEFECTIVE.
|
|
|
